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EM4 at Home

Expressions and equations.

Lesson

Vocabulary

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Parentheses, Exponents, and Calculators

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Solving Problems with Order of Operations

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Expressions and Patterns

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Representing Unknown Quantities with Algebraic Expressions

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Exploring Equations

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The Distributive Property and Equivalent Expressions

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Applying Properties of Arithmetic

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The Banquet Table

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Introduction to Inequalities

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Finding and Graphing Solution Sets of Inequalities

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Inequalities to Represent Real-World Situations

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Absolute Value as Distance

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Absolute Value

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Mean Absolute Deviation

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Unit 4 Progress Check

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lesson 6 homework 4.7 answer key

Everyday Mathematics for Parents: What You Need to Know to Help Your Child Succeed

The University of Chicago School Mathematics Project

University of Chicago Press

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Related Links

Help with algorithms.

Access video tutorials, practice exercises, and information on the research basis and development of various algorithms.

Everyday Mathematics Online

With a login provided by your child's teacher, access resources to help your child with homework or brush up on your math skills.

Parent Connections on Publisher's site

McGraw-Hill Education offers many resources for parents, including tips, activities, and helpful links.

Parent Resources on EverydayMath.com

EverydayMath.com features activity ideas, literature lists, and family resources for the EM curriculum.

Understanding Everyday Mathematics for Parents

Learn more about the EM curriculum and how to assist your child.

The UChicago STEM Education

Working with Trigonometric Ratios

6.1: This Time with Strategies (5 minutes)

CCSS Standards

  • HSG-SRT.C.6

This warm-up uses a problem students didn’t know how to approach at the beginning of the unit. At this point they can try again using the right triangle table. Then when students learn to look up trigonometric ratios in the calculator, that procedure will be solidly grounded in conceptual understanding.

Student Facing

Estimate the value of \(z\) .

Expand image

Student Response

For access, consult one of our IM Certified Partners .

Activity Synthesis

Point out to students this is the triangle they didn’t know how to approach at the beginning of the unit. Now they have a strategy for finding side lengths of right triangles for acute angles included in the right triangle table. The purpose of this lesson is to teach a method that works for any angle, not just the ones in the table.

6.2: New Names, Same Ratios (15 minutes)

Routines and Materials

Instructional Routines

  • MLR8: Discussion Supports

The purpose of this activity is to connect the work students have done in previous lessons and the warm-up to trigonometric ratios. Students learn the names of the trigonometric ratios and how to look them up in the calculator. To continue solidifying their conceptual understanding, students compare the calculator’s value to their work with the right triangle table.

Tell students, “The right triangle table is useful, but what if the angle is not a multiple of 10 degrees? There must be a way to move from estimating to calculating. The name of the column in the right triangle table, 'adjacent leg divided by the hypotenuse,' is long, so mathematicians call this ratio cosine . The column called 'opposite leg divided by the hypotenuse' is named sine . The column called 'opposite leg divided by the adjacent leg' is named tangent . These three names describe trigonometric ratios . Label the columns of the right triangle table with the corresponding trigonometric function names.”

“The word trigonometric comes from the ancient roots of trigon (think about what pentagon or hexagon mean) and metric (like measure). So the word trigonometric comes from ancient words meaning triangle measurement.”

“Cosine, sine, and tangent work like functions where the input is the measure of an angle and the output is a ratio. Scientific calculators can display the ratio for any angle, even ones not included in the table. First, identify that we have an angle measure and the length of the adjacent leg. Then identify that we are looking for the length of the hypotenuse. The ratio of adjacent leg divided by hypotenuse is called cosine. So we can write \(\cos(50)=\frac{3}{z}\) .” Demonstrate how to use the technology available to solve this type of problem. Typing \(\cos(50)\) into the calculator and then substituting gives the new equation \(0.643=\frac{3}{z}\) . (Note: if students don’t get 0.643, check the mode of the calculator. There is no need to discuss the meaning of radians now, but students will see radians later in this course.)

  • Use your calculator to determine the values of \(\cos(50)\) ,  \(\sin(50)\) , and \(\tan(50)\) .
  • Use your calculator to determine the values of \(\cos(40)\) ,  \(\sin(40)\) , and \(\tan(40)\) .
  • How do these values compare to your chart? 
  • Find the value of \(z\) .

Invite students to share their new value for \(z\) . (Solving the equation we wrote in the launch gives \(z=4.7\) units.)

Ask students:

  • “How does this answer compare to using the table?” (It’s the same.)
  • “Which one is more trustworthy?” (All opinions are valid.)
  • “Which one is more accurate?” (The calculator is much more accurate than the table for numbers between decade numbers. The calculator gives more decimal places, and it’s possible to solve without rounding to get a more precise answer.)

Inform students it is also okay to leave answers in the form \(z=\frac{3}{\cos(50)}\)  which would be exact.

Ask students to add these definitions to their reference charts as you add them to the class reference chart:

The cosine of an acute angle in a right triangle is the ratio (quotient) of the length of the adjacent leg to the length of the hypotenuse.

\(\cos(\theta)=\frac{\text{adjacent}}{\text{hypotenuse}}\)

The sine of an acute angle in a right triangle is the ratio (quotient) of the length of the opposite leg to the length of the hypotenuse.

\(\sin(\theta)=\frac{\text{opposite}}{\text{hypotenuse}}\)

The tangent  of an acute angle in a right triangle is the ratio (quotient) of the length of the opposite leg to the length of the adjacent leg.

\(\tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}\)

6.3: Solve These Triangles (15 minutes)

Building On

  • Think Pair Share

Required Materials

  • Scientific calculators

Students apply their new knowledge of trigonometric ratios to solve these problems. Since these problems ask for multiple side and angle measures, there is an increased opportunity for creativity in solving.

Monitor for students who solve multiple trigonometric equations versus those that apply the Pythagorean Theorem.

Arrange students in groups of 2. Ask students to compare their strategy with their partner’s and decide if they are both correct, even if they are different.

Students need not complete all the problems before the discussion.

Solve for \(x\) .

Solve for \(y\) .

Find all the missing sides and angle measures.

The measure of angle \(X\) is 90 degrees and angle \(Y\) is 12 degrees. Side \(XZ\) has length 2 cm.

The measure of angle \(K\) is 90 degrees and angle \(L\) is 71 degrees. Side \(LM\) has length 20 cm.

Are you ready for more?

Complete the table.

angle cosine sine tangent
\(80^\circ\)      
\(85^\circ\)      
\(89^\circ\)      

Based on this information, what do you think are the cosine, sine, and tangent of 90 degrees? Explain or show your reasoning.

Anticipated Misconceptions

If students struggle to get started, prompt them to set up ratios to find the missing sides. If students struggle to set up ratios, prompt them to identify what is known and what they are looking to find by annotating the diagram.

Invite students to contrast solving multiple trigonometric equations versus applying the Pythagorean Theorem to determine the final side length. Is one method easier? More accurate? (The Pythagorean Theorem is more familiar so I prefer it. Both methods are accurate so long as you don't round too much.)

Call attention to the triangle with no marked right angle. Ask students, “How do you know you can use trigonometric functions with this triangle?” (By the Triangle Angle Sum Theorem the third angle must be 90 degrees.)

Lesson Synthesis

Display this triangle and give students quiet work time to write as many equations as they can to show the relationships in triangle \(END\) .

Invite students to share one equation at a time until you have recorded two of each trigonometric ratio ( cosine, sine, and tangent ):

\(\cos(35)=\frac{d}{n}\)

\(\sin(35)=\frac{e}{n}\)

\(\tan(35)=\frac{e}{d}\)

\(\cos(55)=\frac{e}{n}\)

\(\sin(55)=\frac{d}{n}\)

\(\tan(55)=\frac{d}{e}\)

Tell students the value of \(d\) is 6 units. First, ask them to consider which equations would be helpful in solving for the other sides. Then give them time to do the calculations ( \(e=4.2 \) units, \(n=7.3\)  units). If students get slightly different answers, take the opportunity to discuss precision and rounding error.

6.4: Cool-down - Solve That Triangle (5 minutes)

Student lesson summary.

We have a column in the right triangle table for "adjacent leg  \(\div\)  hypotenuse." We use this ratio so frequently it has a name. It is called the cosine of the angle. We write \(\cos(25)\) to say the cosine of 25 degrees. A scientific calculator can display the cosine of any angle. This means we can more precisely calculate unknown side lengths rather than estimating using the table. The right triangle table is sometimes called a trigonometry table since cosine, sine , and tangent are trigonometric ratios . Here is what the table looks like with the ratios labeled with their special names:

cosine sine tangent
angle adjacent leg \(\div\) hypotenuse opposite leg \(\div\) hypotenuse opposite leg \(\div\) adjacent leg
\(25^\circ\) \(\cos(25)=0.906\) \(\sin(25)=0.423\) \(\tan(25)=0.466\)

If the length  \(b\)  is 7, we can find \(c\) by solving the equation \(\cos(25)=\frac{7}{c}\) . So \(c\)  is about 7.7 units. To solve for \(a\) we have 3 choices: the Pythagorean Theorem, sine, and tangent. Let’s use tangent by solving the equation \(\tan(25)=\frac{a}{7}\) . So \(a\)  is about 3.3 units. We can check our answers using the Pythagorean Theorem. It should be true that \(3.3^2+7^2=7.7^2\) . The two expressions are almost equal, which makes sense because we expect some error due to rounding.

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Unit 4 – Linear Functions

Introduction to Linear Functions

LESSON/HOMEWORK

LECCIÓN/TAREA

LESSON VIDEO

EDITABLE LESSON

EDITABLE KEY

SMART NOTEBOOK

More Work Graphing Linear Functions (Lines)

Writing the Equation of a Line

Working with Linear Functions in Table Form

Modeling with Linear Functions

More Modeling with Linear Functions

Equations of Horizontal and Vertical Lines

Piecewise Linear Functions

Step Functions

Absolute Value Functions

The Truth About Graphs

Linear Inequalities with Two Variables

Introduction to Sequences

Arithmetic Sequences

Unit Review

Unit 4 Review

UNIT REVIEW

REPASO DE LA UNIDAD

EDITABLE REVIEW

Unit 4 Assessment – Form A

EDITABLE ASSESSMENT

Unit 4 Assessment – Form B

Unit 4 Exit Tickets

Unit 4 Mid-Unit Quiz – Form A

U04.AO.01 – Modeling the Boundaries of a Shed

PDF DOCUMENT - SPANISH

EDITABLE RESOURCE

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Go Math Grade 6 Answer Key of All Chapters | Middle School Grade 6 Solutions Key

Go Math Grade 6 Answer Key: In Today’s World learning has become demanding than ever before. Finding a reliable source has become a tedious task for anyone out there who wants to upgrade their skills. Sharpen your Math Skills taking the help of 6th Grade Go Math Middle School Solutions Key en route to your math Journey. Middle School Go Math Grade 6 Solutions Key includes Worked Out Solutions for all the Problems in Go Math Textbooks.

Access the Chapterwise Solutions for all the Questions in your Grade 6 Go Math Textbooks and make your learning effective. Grade 6 HMH Go Math Answer Keys develops mathematical understanding among students and also creates interest in the subject. With consistent practice, you can learn and clear the standard tests with flying colors.

Grade 6th Go Math Answer Key

All the solutions of Middle School Go Math Books for Grade 6 are prepared by subject experts. Go Math Books prevailing for 6th Standard are prepared to meet both the content and intent of Middle School. You can witness the Mathematical Concepts explained in a concise manner making it easier for you to have a good grip on the subject. HMH Go Math Grade 6 Answer Key includes the solved examples and practice questions to strengthen your Mathematical Concepts.

Grade 6 HMH Go Math – Answer Keys

  • Chapter 1: Divide Multi-Digit Numbers
  • Chapter 2: Fractions and Decimals
  • Chapter 3: Understand Positive and Negative Numbers
  • Chapter 4: Model Ratios
  • Chapter 5: Model Percents
  • Chapter 6: Convert Units of Length
  • Chapter 7: Exponents
  • Chapter 8: Solutions of Equations
  • Chapter 9: Independent and Dependent Variables
  • Chapter 10: Area of Parallelograms
  • Chapter 11: Surface Area and Volume
  • Chapter 12: Data Displays and Measures of Center
  • Chapter 13: Variability and Data Distributions

Grade 6 McGraw Hill Glencoe – Answer Keys

  • Chapter 1: Ratios and Rates
  • Chapter 2: Fractions, Decimals, and Percents
  • Chapter 3: Compute with Multi-Digit Numbers
  • Chapter 4: Multiply and Divide Fractions
  • Chapter 5: Integers and Coordinate Plane
  • Chapter 6: Expressions
  • Chapter 7: Equations
  • Chapter 8: Functions and Inequalities
  • Chapter 9: Area
  • Chapter 10: Volume and Surface Area
  • Chapter 11: Statistical Measures
  • Chapter 12: Statistical Display

Go Math Middle School Grade 6 Answer Key of all Chapters

Avail Grade 6 Solutions provided over here and understand the concepts in a better way.  Identify the Knowledge Gap and allot time to the areas you feel difficult. Detailed description provided in the Go Math Grade 6th Solutions Key reflects more of the topics in your Middle School Textbooks. You can use them during your Homework or while preparing for Tests. Tap on the respective chapter you wish to practice and clarify all your concerns at one go.

Why to read Go Math 6th Std. Solutions Key?

There are plenty of benefits that come with solving the Go Math 6th Standard Answer Key. Refer to them and know the need of practicing through Grade 6 HMH Go Math Answer Key. They are as follows

  • Go Math Answer Key for Grade 6 ensures success for every learner.
  • Middle School Go Math Solutions Key makes learning easier for both Students and Teachers.
  • Elaborate Explanation provided to all the Math Practice Problems helps you enhance your subject knowledge.
  • Go Math Grade 6 Answer Key lays a stronger foundation of Fundamentals of your Mathematical Concepts.

Why To Read Go Math 6th Std. Solutions Key

FAQs on Grade 6 Go Math Answer Key

1.  Where Can I get Go Math Grade 6 Answer Key PDF?

You can get Go Math Grade 6th Answer Key PDF for all the chapters on our page.

2. Which Website offers the best resources on Go Math Grade 6 Answer Key?

ccssmathanswers.com is a trustworthy site for all your needs and provides reliable information on Go Math Answer Key for Class 6th. Take your preparation to the next level and score better grades in your exams.

3. Where can I find Chapterwise Solutions of Go Math 6th Grade Problems?

You can find the Go Math 6th Std Solutions Key of all Chapters on our page. Simply prepare the Chapter you want to access through the direct links and learn accordingly.

4. How to Learn 6th Grade Math Concepts easily?

Learning concepts from the Go Math Middle School Answer Key for Grade 6 makes you familiar with a variety of questions. Thereby, you can prepare effectively and clear your tests with higher grades.

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